What is the answer to x^2+2x+sqrt(x^2+2x+10)-20=0 ?

The answer to x^2+2x+sqrt(x^2+2x+10)-20=0 is x=3,x=-5

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x^2+2x+sqrt(x^2+2x+10)-20=0

x^{2} + 2 x + x^{2} + 2 x + 10 - 20 = 0

x = 3, x = - 5

Solution steps

x^{2} + 2 x + x^{2} + 2 x + 10 - 20 = 0

Remove square roots

x^{2} + 2 x + 10 = x^{4} + 4 x^{3} - 36 x^{2} - 80 x + 400

Solve

x^{2} + 2 x + 10 = x^{4} + 4 x^{3} - 36 x^{2} - 80 x + 400 : x = 3, x = - 5, x = - 1 + 33, x = - 1 - 33

x = 3, x = - 5, x = - 1 + 33, x = - 1 - 33

Verify Solutions:

x = 3

True

, x = - 5

True

, x = - 1 + 33

False

, x = - 1 - 33

False

The solutions are

x = 3, x = - 5

2624 x^{2} + 1240 x + 25600 = 260

x^{- \frac{1}{2}} = \frac{1}{x}

3 x^{2} + 8 x + 5 = 33 x^{2} + 76 x + 35

(\frac{x}{1 + x ^{2}}) = 2 - 1

\frac{1}{5} = \frac{1}{2 c}

What is the answer to x^2+2x+sqrt(x^2+2x+10)-20=0 ?
The answer to x^2+2x+sqrt(x^2+2x+10)-20=0 is x=3,x=-5
Solve for x: x^2+2x+sqrt(x^2+2x+10)-20=0
The solution is x=3,x=-5