What is the answer to roots \sqrt[3]{-4bx^2+c} ?

The answer to roots \sqrt[3]{-4bx^2+c} is x=(sqrt(c))/(2sqrt(b)),x=-(sqrt(c))/(2sqrt(b))

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roots \sqrt[3]{-4bx^2+c}

roots

x = \frac{c}{2 b}, x = - \frac{c}{2 b}

Solution steps

The roots are the intercepts with the x-axis

(y = 0)

Take both sides of the equation to the power of

3 : - 4 b x^{2} + c = 0

- 4 b x^{2} + c = 0

Solve

- 4 b x^{2} + c = 0 : x = \frac{c}{2 b}, x = - \frac{c}{2 b}

x = \frac{c}{2 b}, x = - \frac{c}{2 b}

4 x - 8 = 2

\frac{1}{2 x} - \frac{1}{7} = 0

3 x + 5 = 2 - 2 x

What is the answer to roots \sqrt[3]{-4bx^2+c} ?
The answer to roots \sqrt[3]{-4bx^2+c} is x=(sqrt(c))/(2sqrt(b)),x=-(sqrt(c))/(2sqrt(b))