What are the solutions to the equation 3x^2+6x-24=0 ?

The solutions to the equation 3x^2+6x-24=0 are x=2,x=-4

Find the zeros of 3x^2+6x-24=0

The zeros of 3x^2+6x-24=0 are x=2,x=-4

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3 x^{2} + 6 x - 24 = 0

x = 2, x = - 4

Solution steps

3 x^{2} + 6 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 24) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 3}, x_{2} = \frac{- 6 - 18}{2 \cdot 3}

x = \frac{- 6 + 18}{2 \cdot 3} : 2

x = \frac{- 6 - 18}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

7 x - 4 + 3 x = 2 x - 4 + 16

\frac{4.5 \cdot 1 0 ^{- 9}}{8.85 \cdot 1 0 ^{- 12}}

32 m^{2} + 8 m = - 3 m^{2} - 3 m + 6

\frac{6 x h + 3 h ^{2}}{h}

What are the solutions to the equation 3x^2+6x-24=0 ?
The solutions to the equation 3x^2+6x-24=0 are x=2,x=-4
Find the zeros of 3x^2+6x-24=0
The zeros of 3x^2+6x-24=0 are x=2,x=-4