What is the answer to x^2+2x+3=sqrt(4-x^2) ?

The answer to x^2+2x+3=sqrt(4-x^2) is No Solution for x\in\mathbb{R}

Solve for x: x^2+2x+3=sqrt(4-x^2)

The solution is No Solution for x\in\mathbb{R}

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x^{2} + 2 x + 3 = 4 - x^{2}

No Solution for x \in R

Solution steps

x^{2} + 2 x + 3 = 4 - x^{2}

Square both sides:

x^{4} + 4 x^{3} + 10 x^{2} + 12 x + 9 = 4 - x^{2}

x^{4} + 4 x^{3} + 10 x^{2} + 12 x + 9 = 4 - x^{2}

Solve

x^{4} + 4 x^{3} + 10 x^{2} + 12 x + 9 = 4 - x^{2} :

No Solution for

x \in R

No Solution for x \in R

15 - 3 x - 1 = x

9 x - 3 = 4 x - 4

x^{- \frac{2}{3}} = 0

4 x - \frac{32}{x} = 0

y, x y - y = x^{2} + y^{2}

What is the answer to x^2+2x+3=sqrt(4-x^2) ?
The answer to x^2+2x+3=sqrt(4-x^2) is No Solution for x\in\mathbb{R}
Solve for x: x^2+2x+3=sqrt(4-x^2)
The solution is No Solution for x\in\mathbb{R}