What is the answer to cube root of 8r+1}=\sqrt[3]{r+8 ?

The answer to cube root of 8r+1}=\sqrt[3]{r+8 is r=1

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cube root of 8r+1}=\sqrt[3]{r+8

3 8 r + 1 = 3 r + 8

r = 1

Solution steps

3 8 r + 1 = 3 r + 8

Take both sides of the equation to the power of

3 : 8 r + 1 = r + 8

8 r + 1 = r + 8

Solve

8 r + 1 = r + 8 : r = 1

r = 1

Verify Solutions:

r = 1

True

The solution is

r = 1

y = \frac{y + 2}{5 - y}

5 x + 14 - x = 8

40 x = 5 x + 3

2 h - 5 = 1 - h - 3

8 x^{2} + 144 - 3 x = 0

What is the answer to cube root of 8r+1}=\sqrt[3]{r+8 ?
The answer to cube root of 8r+1}=\sqrt[3]{r+8 is r=1
Solve for r: cube root of 8r+1}=\sqrt[3]{r+8
The solution is r=1