What is the answer to x-sqrt(x^2-3)=sqrt(x-1) ?

The answer to x-sqrt(x^2-3)=sqrt(x-1) is x=2

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x-sqrt(x^2-3)=sqrt(x-1)

x - x^{2} - 3 = x - 1

x = 2

Solution steps

x - x^{2} - 3 = x - 1

Remove square roots

4 x^{4} - 12 x^{2} = 4 x^{4} - 4 x^{3} - 7 x^{2} + 4 x + 4

Solve

4 x^{4} - 12 x^{2} = 4 x^{4} - 4 x^{3} - 7 x^{2} + 4 x + 4 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

16 = 7 + 11 - 7 n

x^{\frac{- 1}{3}} - 1 = 0

2 x + 5 x = 3

x + 25 = x - 5

x, z = x y

What is the answer to x-sqrt(x^2-3)=sqrt(x-1) ?
The answer to x-sqrt(x^2-3)=sqrt(x-1) is x=2
Solve for x: x-sqrt(x^2-3)=sqrt(x-1)
The solution is x=2