What is the answer to 1= x/(sqrt(9-x^2)) ?

The answer to 1= x/(sqrt(9-x^2)) is x= 3/(sqrt(2))

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1= x/(sqrt(9-x^2))

1 = \frac{x}{9 - x ^{2}}

x = \frac{3}{2}

Decimal

x = 2.12132 \dots

Solution steps

1 = \frac{x}{9 - x ^{2}}

Multiply both sides by

9 - x^{2}

1 \cdot 9 - x^{2} = \frac{x}{9 - x ^{2}} 9 - x^{2}

Simplify

9 - x^{2} = x

Square both sides:

9 - x^{2} = x^{2}

9 - x^{2} = x^{2}

Solve

9 - x^{2} = x^{2} : x = \frac{3}{2}, x = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

, x = - \frac{3}{2}

False

The solution is

x = \frac{3}{2}

15 - 2 x = 3

x + 2 2 x + 3 = 3

\frac{4 x - 2}{3 x ^{\frac{2}{3}}} = 0

x - 4 = - x + 6

5 x - 1 - x + 6 = 3

What is the answer to 1= x/(sqrt(9-x^2)) ?
The answer to 1= x/(sqrt(9-x^2)) is x= 3/(sqrt(2))
Solve for x: 1= x/(sqrt(9-x^2))
The solution is x= 3/(sqrt(2))