What is the answer to sqrt(1-x)=x^3+3x^2+3x+2 ?

The answer to sqrt(1-x)=x^3+3x^2+3x+2 is x\approx-0.42243…

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sqrt(1-x)=x^3+3x^2+3x+2

1 - x = x^{3} + 3 x^{2} + 3 x + 2

x \approx - 0.42243 \dots

Solution steps

1 - x = x^{3} + 3 x^{2} + 3 x + 2

Square both sides:

1 - x = x^{6} + 6 x^{5} + 15 x^{4} + 22 x^{3} + 21 x^{2} + 12 x + 4

1 - x = x^{6} + 6 x^{5} + 15 x^{4} + 22 x^{3} + 21 x^{2} + 12 x + 4

Solve

1 - x = x^{6} + 6 x^{5} + 15 x^{4} + 22 x^{3} + 21 x^{2} + 12 x + 4 : x \approx - 0.42243 \dots, x \approx - 2.41757 \dots

x \approx - 0.42243 \dots, x \approx - 2.41757 \dots

Verify Solutions:

x \approx - 0.42243 \dots

True

, x \approx - 2.41757 \dots

False

The solution is

x \approx - 0.42243 \dots

3 3 x - 1 = 2 3 (2 x - 1)

\frac{x + 5 - 4}{2 x + 1 - 2} = - 1

x - 5 = - 2 x + 18

2 - x = 8 - 7 x

4 x + 2 = 3 x + 4

What is the answer to sqrt(1-x)=x^3+3x^2+3x+2 ?
The answer to sqrt(1-x)=x^3+3x^2+3x+2 is x\approx-0.42243…
Solve for x: sqrt(1-x)=x^3+3x^2+3x+2
The solution is x\approx-0.42243…