What is the answer to sqrt(4x^2-9)=2sqrt(2x+3) ?

The answer to sqrt(4x^2-9)=2sqrt(2x+3) is x= 7/2 ,x=-3/2

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sqrt(4x^2-9)=2sqrt(2x+3)

4 x^{2} - 9 = 2 2 x + 3

x = \frac{7}{2}, x = - \frac{3}{2}

Decimal

x = 3.5, x = - 1.5

Solution steps

4 x^{2} - 9 = 2 2 x + 3

Square both sides:

4 x^{2} - 9 = 8 x + 12

4 x^{2} - 9 = 8 x + 12

Solve

4 x^{2} - 9 = 8 x + 12 : x = \frac{7}{2}, x = - \frac{3}{2}

x = \frac{7}{2}, x = - \frac{3}{2}

Verify Solutions:

x = \frac{7}{2}

True

, x = - \frac{3}{2}

True

The solutions are

x = \frac{7}{2}, x = - \frac{3}{2}

x + 4 - 6 - x = - 2

x^{2} - 1 = 3 - x^{2}

9 - x = 0

y, y^{\frac{2}{3}} = x

70 - x - 54 - x = 2

What is the answer to sqrt(4x^2-9)=2sqrt(2x+3) ?
The answer to sqrt(4x^2-9)=2sqrt(2x+3) is x= 7/2 ,x=-3/2
Solve for x: sqrt(4x^2-9)=2sqrt(2x+3)
The solution is x= 7/2 ,x=-3/2