What is the answer to sqrt(2-x^2)+sqrt(4-x^2)=2x ?

The answer to sqrt(2-x^2)+sqrt(4-x^2)=2x is x=(sqrt(3+\sqrt{7)})/2

Solve for x: sqrt(2-x^2)+sqrt(4-x^2)=2x

The solution is x=(sqrt(3+\sqrt{7)})/2

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2 - x^{2} + 4 - x^{2} = 2 x

x = \frac{3 + 7}{2}

Decimal

x = 1.18803 \dots

Solution steps

2 - x^{2} + 4 - x^{2} = 2 x

Remove square roots

16 x^{4} + 16 x^{2} + 4 = 64 x^{2} - 16 x^{4}

Solve

16 x^{4} + 16 x^{2} + 4 = 64 x^{2} - 16 x^{4} : x = \frac{3 + 7}{2}, x = - \frac{3 + 7}{2}, x = \frac{3 - 7}{2}, x = - \frac{3 - 7}{2}

x = \frac{3 + 7}{2}, x = - \frac{3 + 7}{2}, x = \frac{3 - 7}{2}, x = - \frac{3 - 7}{2}

Verify Solutions:

x = \frac{3 + 7}{2}

True

, x = - \frac{3 + 7}{2}

False

, x = \frac{3 - 7}{2}

False

, x = - \frac{3 - 7}{2}

False

The solution is

x = \frac{3 + 7}{2}

\frac{37 - 2 x ^{2}}{37 - x ^{2}} = 0

4 x + 9 = x + 1

- 4 = - 4 - 4 - p

7 = 1.7 s + 4.5 - 3.5

x + 4 = 3

What is the answer to sqrt(2-x^2)+sqrt(4-x^2)=2x ?
The answer to sqrt(2-x^2)+sqrt(4-x^2)=2x is x=(sqrt(3+\sqrt{7)})/2
Solve for x: sqrt(2-x^2)+sqrt(4-x^2)=2x
The solution is x=(sqrt(3+\sqrt{7)})/2