What is the answer to \sqrt[4]{x+8}=\sqrt[4]{2x-2} ?

The answer to \sqrt[4]{x+8}=\sqrt[4]{2x-2} is x=10

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\sqrt[4]{x+8}=\sqrt[4]{2x-2}

4 x + 8 = 4 2 x - 2

x = 10

Solution steps

4 x + 8 = 4 2 x - 2

Take both sides of the equation to the power of

4 : x + 8 = 2 x - 2

x + 8 = 2 x - 2

Solve

x + 8 = 2 x - 2 : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

\frac{1}{x} = 1

x + 9 + x = 9

6 + x - x^{2} = 1 - x

x - 3 = 9

4 x - 2 = 9 x + 7

What is the answer to \sqrt[4]{x+8}=\sqrt[4]{2x-2} ?
The answer to \sqrt[4]{x+8}=\sqrt[4]{2x-2} is x=10
Solve for x: \sqrt[4]{x+8}=\sqrt[4]{2x-2}
The solution is x=10