What are the solutions to the equation x^2+2x-4=-9 ?

The solutions to the equation x^2+2x-4=-9 are x=-1+2i,x=-1-2i

Find the zeros of x^2+2x-4=-9

The zeros of x^2+2x-4=-9 are x=-1+2i,x=-1-2i

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x^{2} + 2 x - 4 = - 9

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{2} + 2 x - 4 = - 9

Move

9

to the left side

x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

x_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

x = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

4 - (- 1)

\frac{5}{8} - \frac{2}{5}

f^{2} + 5 f + 6

∣ - 4 w + 2 ∣ = 14

4 w + 3 w - 6 w = w + 15 + 2 w - 3 w

What are the solutions to the equation x^2+2x-4=-9 ?
The solutions to the equation x^2+2x-4=-9 are x=-1+2i,x=-1-2i
Find the zeros of x^2+2x-4=-9
The zeros of x^2+2x-4=-9 are x=-1+2i,x=-1-2i