What is the answer to 3x-2sqrt(x^2+9)=0 ?

The answer to 3x-2sqrt(x^2+9)=0 is x= 6/(sqrt(5))

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3x-2sqrt(x^2+9)=0

3 x - 2 x^{2} + 9 = 0

x = \frac{6}{5}

Decimal

x = 2.68328 \dots

Solution steps

3 x - 2 x^{2} + 9 = 0

Remove square roots

4 x^{2} + 36 = 9 x^{2}

Solve

4 x^{2} + 36 = 9 x^{2} : x = \frac{6}{5}, x = - \frac{6}{5}

x = \frac{6}{5}, x = - \frac{6}{5}

Verify Solutions:

x = \frac{6}{5}

True

, x = - \frac{6}{5}

False

The solution is

x = \frac{6}{5}

3 - x + x - 7 - 1 - x = 9

x^{2} - 1 = x^{2} - 5

x^{3} + 3 x - 2 = 2

x - 3 - 2 x = - 6

y, y^{\frac{1}{3}} = x

What is the answer to 3x-2sqrt(x^2+9)=0 ?
The answer to 3x-2sqrt(x^2+9)=0 is x= 6/(sqrt(5))
Solve for x: 3x-2sqrt(x^2+9)=0
The solution is x= 6/(sqrt(5))