What is the answer to sqrt(2x+\sqrt{6x^2+1)}=x+1 ?

The answer to sqrt(2x+\sqrt{6x^2+1)}=x+1 is x=2,x=0

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sqrt(2x+\sqrt{6x^2+1)}=x+1

2 x + 6 x^{2} + 1 = x + 1

x = 2, x = 0

Solution steps

2 x + 6 x^{2} + 1 = x + 1

Remove square roots

6 x^{2} + 1 = x^{4} + 2 x^{2} + 1

Solve

6 x^{2} + 1 = x^{4} + 2 x^{2} + 1 : x = 2, x = - 2, x = 0

x = 2, x = - 2, x = 0

Verify Solutions:

x = 2

True

, x = - 2

False

, x = 0

True

The solutions are

x = 2, x = 0

x^{\frac{2}{3}} - 3 x^{\frac{1}{3}} - 18 = 0

3 3 9 p = - 12

x + 16 - x = 2

x + 5 = 7 x + 29

5 - 2 x + 5 = 12

What is the answer to sqrt(2x+\sqrt{6x^2+1)}=x+1 ?
The answer to sqrt(2x+\sqrt{6x^2+1)}=x+1 is x=2,x=0
Solve for x: sqrt(2x+\sqrt{6x^2+1)}=x+1
The solution is x=2,x=0