What is the answer to 3+sqrt(x^2-3)=x^2 ?

The answer to 3+sqrt(x^2-3)=x^2 is x=2,x=-2,x=sqrt(3),x=-sqrt(3)

Solve for x: 3+sqrt(x^2-3)=x^2

The solution is x=2,x=-2,x=sqrt(3),x=-sqrt(3)

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3 + x^{2} - 3 = x^{2}

x = 2, x = - 2, x = 3, x = - 3

Decimal

x = 2, x = - 2, x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

3 + x^{2} - 3 = x^{2}

Remove square roots

x^{2} - 3 = x^{4} - 6 x^{2} + 9

Solve

x^{2} - 3 = x^{4} - 6 x^{2} + 9 : x = 2, x = - 2, x = 3, x = - 3

x = 2, x = - 2, x = 3, x = - 3

Verify Solutions:

x = 2

True

, x = - 2

True

, x = 3

True

, x = - 3

True

The solutions are

x = 2, x = - 2, x = 3, x = - 3

x - x = x

2 x - 1 = 1 - 2 x

x^{2} - x - 7 = x + 3

x - 7 = x - 7

11 x - 28 = x

What is the answer to 3+sqrt(x^2-3)=x^2 ?
The answer to 3+sqrt(x^2-3)=x^2 is x=2,x=-2,x=sqrt(3),x=-sqrt(3)
Solve for x: 3+sqrt(x^2-3)=x^2
The solution is x=2,x=-2,x=sqrt(3),x=-sqrt(3)