What is the answer to \sqrt[3]{2x+7}+6=3 ?

The answer to \sqrt[3]{2x+7}+6=3 is x=-17

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\sqrt[3]{2x+7}+6=3

3 2 x + 7 + 6 = 3

x = - 17

Solution steps

3 2 x + 7 + 6 = 3

Move

6

to the right side

3 2 x + 7 = - 3

Take both sides of the equation to the power of

3 : 2 x + 7 = - 27

2 x + 7 = - 27

Solve

2 x + 7 = - 27 : x = - 17

x = - 17

Verify Solutions:

x = - 17

True

The solution is

x = - 17

x^{2} + 8 - 1 = 2 x

x - 3 + 1 = 6

x + 2 x + 1 = 17

2 x^{\frac{3}{4}} = 16

0 = \frac{x}{5} - 5

What is the answer to \sqrt[3]{2x+7}+6=3 ?
The answer to \sqrt[3]{2x+7}+6=3 is x=-17
Solve for x: \sqrt[3]{2x+7}+6=3
The solution is x=-17