What is the answer to 2x=sqrt(-2x+5-1) ?

The answer to 2x=sqrt(-2x+5-1) is x=(-1+sqrt(17))/4

Solve for x: 2x=sqrt(-2x+5-1)

The solution is x=(-1+sqrt(17))/4

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2 x = - 2 x + 5 - 1

x = \frac{- 1 + 17}{4}

Decimal

x = 0.78077 \dots

Solution steps

2 x = - 2 x + 5 - 1

Square both sides:

4 x^{2} = - 2 x + 4

4 x^{2} = - 2 x + 4

Solve

4 x^{2} = - 2 x + 4 : x = \frac{- 1 + 17}{4}, x = - \frac{1 + 17}{4}

x = \frac{- 1 + 17}{4}, x = - \frac{1 + 17}{4}

Verify Solutions:

x = \frac{- 1 + 17}{4}

True

, x = - \frac{1 + 17}{4}

False

The solution is

x = \frac{- 1 + 17}{4}

4 x + 8 = 5

9 = 6 - 6 n + 3

2 x - 1 + x^{2} = 0

r, r (t) = 1 0^{2} t

- 4 = - 4 1 - 8 b

What is the answer to 2x=sqrt(-2x+5-1) ?
The answer to 2x=sqrt(-2x+5-1) is x=(-1+sqrt(17))/4
Solve for x: 2x=sqrt(-2x+5-1)
The solution is x=(-1+sqrt(17))/4