What is the answer to sqrt(2x^2+8x+1)-x=3 ?

The answer to sqrt(2x^2+8x+1)-x=3 is x=2

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sqrt(2x^2+8x+1)-x=3

2 x^{2} + 8 x + 1 - x = 3

x = 2

Solution steps

2 x^{2} + 8 x + 1 - x = 3

Remove square roots

2 x^{2} + 8 x + 1 = 9 + 6 x + x^{2}

Solve

2 x^{2} + 8 x + 1 = 9 + 6 x + x^{2} : x = 2, x = - 4

x = 2, x = - 4

Verify Solutions:

x = 2

True

, x = - 4

False

The solution is

x = 2

x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} - 6 = 0

x - 2 = - 3

x^{- \frac{1}{2}} = 1

3 x + x + 1 = 7

x, x - 4 + 5 = 3 x + 3

What is the answer to sqrt(2x^2+8x+1)-x=3 ?
The answer to sqrt(2x^2+8x+1)-x=3 is x=2
Solve for x: sqrt(2x^2+8x+1)-x=3
The solution is x=2