What is (2x^2)/((2xy^{-2))^{-1}*2x^{-2}y^2} ?

The solution to (2x^2)/((2xy^{-2))^{-1}*2x^{-2}y^2} is (2x^5)/(y^4)

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simplify (2x^2)/((2xy^{-2))^{-1}*2x^{-2}y^2}

simplify

\frac{2 x ^{2}}{( 2 x y ^{- 2} ) ^{- 1} \cdot 2 x ^{- 2} y ^{2}}

\frac{2 x ^{5}}{y ^{4}}

Solution steps

\frac{2 x ^{2}}{( 2 x y ^{- 2} ) ^{- 1} \cdot 2 x ^{- 2} y ^{2}}

Cancel the common factor:

2

= \frac{x ^{2}}{( 2 x y ^{- 2} ) ^{- 1} x ^{- 2} y ^{2}}

Simplify

\frac{x ^{2}}{x ^{- 2}} : x^{4}

= \frac{x ^{4}}{( 2 x y ^{- 2} ) ^{- 1} y ^{2}}

Simplify

\frac{x ^{4}}{( 2 x y ^{- 2} ) ^{- 1} y ^{2}} : \frac{x ^{5} \cdot 2}{y ^{4}}

= \frac{x ^{5} \cdot 2}{y ^{4}}

= \frac{2 x ^{5}}{y ^{4}}

(4 x - 3) (2 x - 1) \geq 0

3 x^{3} + 5 x^{2} - 6 x - 10

- 2 x \geq 8

17 - 2 x = - 1

\frac{3}{8} - \frac{4}{5}

What is (2x^2)/((2xy^{-2))^{-1}*2x^{-2}y^2} ?
The solution to (2x^2)/((2xy^{-2))^{-1}*2x^{-2}y^2} is (2x^5)/(y^4)