What is factor 2y^2-7y+5 ?

The solution to factor 2y^2-7y+5 is (y-1)(2y-5)

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factor 2y^2-7y+5

factor

2 y^{2} - 7 y + 5

(y - 1) (2 y - 5)

Solution steps

2 y^{2} - 7 y + 5

Break the expression into groups

= (2 y^{2} - 2 y) + (- 5 y + 5)

Factor out

2 y

from

2 y^{2} - 2 y : 2 y (y - 1)

Factor out

- 5

from

- 5 y + 5 : - 5 (y - 1)

= 2 y (y - 1) - 5 (y - 1)

Factor out common term

y - 1

= (y - 1) (2 y - 5)

x^{2} - 17 x - 60

- 3 (x + 1) + \frac{9}{10} = 9

9 z^{2} + 29 = 36 z

a^{5} \cdot a^{- 3}

(X + 5) (X - 1) (X - 2) > 0