What is the answer to solvefor k,Y=10*2k^{0.5}k^{0.4} ?

The answer to solvefor k,Y=10*2k^{0.5}k^{0.4} is k=(Y/(20))^{10/9}

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solvefor k,Y=10*2k^{0.5}k^{0.4}

solve for

k, Y = 10 \cdot 2 k^{0.5} k^{0.4}

k = (\frac{Y}{20})^{\frac{10}{9}}

Solution steps

Y = 10 \cdot 2 k^{0.5} k^{0.4}

Expand

10 \cdot 2 k^{\frac{1}{2}} k^{0.4} : 20 k^{\frac{1}{2} + 0.4}

Y = 20 k^{\frac{1}{2} + 0.4}

Switch sides

20 k^{\frac{1}{2} + 0.4} = Y

Divide both sides by

20

k^{\frac{1}{2} + 0.4} = \frac{Y}{20}

Take both sides of the equation to the power of

\frac{10}{9} : k = (\frac{Y}{20})^{\frac{10}{9}}

k = (\frac{Y}{20})^{\frac{10}{9}}

Verify Solutions:

k = (\frac{Y}{20})^{\frac{10}{9}}

True

The solution is

k = (\frac{Y}{20})^{\frac{10}{9}}

x x - 1 + x x - 1 = 4

\frac{1}{x + 5} = - 2 x

x + 2 - x - 4 = 0

1222 n - 1222 n - 1 = 159

3 x + 4 - 2 = 2

What is the answer to solvefor k,Y=10*2k^{0.5}k^{0.4} ?
The answer to solvefor k,Y=10*2k^{0.5}k^{0.4} is k=(Y/(20))^{10/9}