What is the answer to solvefor y,sqrt(xy)+4=y ?

The answer to solvefor y,sqrt(xy)+4=y is y=(8+x+sqrt(x^2+16x))/2 ,y=(8+x-sqrt(x^2+16x))/2

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solvefor y,sqrt(xy)+4=y

solve for

y, x y + 4 = y

y = \frac{8 + x + x ^{2} + 16 x}{2}, y = \frac{8 + x - x ^{2} + 16 x}{2}

Solution steps

x y + 4 = y

Remove square roots

x y = y^{2} - 8 y + 16

Solve

x y = y^{2} - 8 y + 16 : y = \frac{8 + x + x ^{2} + 16 x}{2}, y = \frac{8 + x - x ^{2} + 16 x}{2}

y = \frac{8 + x + x ^{2} + 16 x}{2}, y = \frac{8 + x - x ^{2} + 16 x}{2}

Verify Solutions:

y = \frac{8 + x + x ^{2} + 16 x}{2}

True

, y = \frac{8 + x - x ^{2} + 16 x}{2}

True

The solutions are

y = \frac{8 + x + x ^{2} + 16 x}{2}, y = \frac{8 + x - x ^{2} + 16 x}{2}

3 6 x - 5 = 3 3 x + 8

x = 7 x - 6

y, x = 2 y - y

6 + x - x^{2} = 9

x^{- \frac{1}{2}} = x

What is the answer to solvefor y,sqrt(xy)+4=y ?
The answer to solvefor y,sqrt(xy)+4=y is y=(8+x+sqrt(x^2+16x))/2 ,y=(8+x-sqrt(x^2+16x))/2