What is the answer to 1-1/(3\sqrt[3]{t^2)}=0 ?

The answer to 1-1/(3\sqrt[3]{t^2)}=0 is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))

Solve for t: 1-1/(3\sqrt[3]{t^2)}=0

The solution is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))

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1 - \frac{1}{3 3 t ^{2}} = 0

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

Decimal

t = 0.19245 \dots, t = - 0.19245 \dots

Solution steps

1 - \frac{1}{3 3 t ^{2}} = 0

Multiply both sides by

3 3 t^{2}

1 \cdot 3 3 t^{2} - \frac{1}{3 3 t ^{2}} \cdot 3 3 t^{2} = 0 \cdot 3 3 t^{2}

Simplify

3 3 t^{2} - 1 = 0

Move

1

to the right side

3 3 t^{2} = 1

Divide both sides by

3

3 t^{2} = \frac{1}{3}

Take both sides of the equation to the power of

3 : t^{2} = \frac{1}{27}

t^{2} = \frac{1}{27}

Solve

t^{2} = \frac{1}{27} : t = \frac{1}{3 3}, t = - \frac{1}{3 3}

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

Verify Solutions:

t = \frac{1}{3 3}

True

, t = - \frac{1}{3 3}

True

The solutions are

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

w, 29 + 4 w = 23 - c w

\frac{1}{2 x + 9} = \frac{1}{8}

2 x - 3 = 11

y, 3 x^{2} + 3 y^{2} = 1

2 x - 1 = 0

What is the answer to 1-1/(3\sqrt[3]{t^2)}=0 ?
The answer to 1-1/(3\sqrt[3]{t^2)}=0 is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))
Solve for t: 1-1/(3\sqrt[3]{t^2)}=0
The solution is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))