What is the answer to \sqrt[4]{3x+7}=\sqrt[4]{2x+13} ?

The answer to \sqrt[4]{3x+7}=\sqrt[4]{2x+13} is x=6

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\sqrt[4]{3x+7}=\sqrt[4]{2x+13}

4 3 x + 7 = 4 2 x + 13

x = 6

Solution steps

4 3 x + 7 = 4 2 x + 13

Take both sides of the equation to the power of

4 : 3 x + 7 = 2 x + 13

3 x + 7 = 2 x + 13

Solve

3 x + 7 = 2 x + 13 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

\frac{5 x - 12}{3 x ^{\frac{1}{3}}} = 0

2 x + x = 4

t + 7 t = 0

x^{2} - 6 x + 9 = 4

3 = 2 x

What is the answer to \sqrt[4]{3x+7}=\sqrt[4]{2x+13} ?
The answer to \sqrt[4]{3x+7}=\sqrt[4]{2x+13} is x=6
Solve for x: \sqrt[4]{3x+7}=\sqrt[4]{2x+13}
The solution is x=6