What is the answer to 6+\sqrt[3]{y-4}=9 ?

The answer to 6+\sqrt[3]{y-4}=9 is y=31

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6+\sqrt[3]{y-4}=9

6 + 3 y - 4 = 9

y = 31

Solution steps

6 + 3 y - 4 = 9

Move

6

to the right side

3 y - 4 = 3

Take both sides of the equation to the power of

3 : y - 4 = 27

y - 4 = 27

Solve

y - 4 = 27 : y = 31

y = 31

Verify Solutions:

y = 31

True

The solution is

y = 31

x - 2 - 1 = 3 - x

3 3 x + 4 - x = 5 + x

6 + \frac{6}{x ^{\frac{5}{11}}} = 0

2 2 x - 8 = 3 (2 x + 2)

16 - x^{\frac{2}{3}} = 0

What is the answer to 6+\sqrt[3]{y-4}=9 ?
The answer to 6+\sqrt[3]{y-4}=9 is y=31
Solve for y: 6+\sqrt[3]{y-4}=9
The solution is y=31