What is the answer to log_{10}(x)+log_{10}(2)=log_{10}(5) ?

The answer to log_{10}(x)+log_{10}(2)=log_{10}(5) is x= 5/2

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log_{10}(x)+log_{10}(2)=log_{10}(5)

lo g_{10} (x) + lo g_{10} (2) = lo g_{10} (5)

x = \frac{5}{2}

Decimal

x = 2.5

Solution steps

lo g_{10} (x) + lo g_{10} (2) = lo g_{10} (5)

Move

lo g_{10} (2)

to the right side

lo g_{10} (x) = lo g_{10} (5) - lo g_{10} (2)

Apply log rules

x = \frac{5}{2}

Verify Solutions:

x = \frac{5}{2}

True

The solution is

x = \frac{5}{2}

x, ln (y) = m ln (x) + ln (b)

x, y = ln (x)

lo g_{10} (2 x) = 3

x^{l o g_{10} (x)} = 100 x

lo g_{a} (x)

What is the answer to log_{10}(x)+log_{10}(2)=log_{10}(5) ?
The answer to log_{10}(x)+log_{10}(2)=log_{10}(5) is x= 5/2
Solve for x: log_{10}(x)+log_{10}(2)=log_{10}(5)
The solution is x= 5/2