What is the answer to log_{10}(x^2)+log_{10}(25)=2 ?

The answer to log_{10}(x^2)+log_{10}(25)=2 is x=2,x=-2

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log_{10}(x^2)+log_{10}(25)=2

lo g_{10} (x^{2}) + lo g_{10} (25) = 2

x = 2, x = - 2

Solution steps

lo g_{10} (x^{2}) + lo g_{10} (25) = 2

Move

lo g_{10} (25)

to the right side

lo g_{10} (x^{2}) = 2 - lo g_{10} (25)

Apply log rules

x^{2} = 4

Solve

x^{2} = 4 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

2 ln (x) - ln (2 x - 3) = ln (5 x) - ln (x + 2)

2 x ln (x) + x = 0

lo g_{b} (x)

2 lo g_{10} (x - 1) = lo g_{10} (2 x + 2)

lo g_{10} (x - 2) + lo g_{10} (12 - x) = 0

What is the answer to log_{10}(x^2)+log_{10}(25)=2 ?
The answer to log_{10}(x^2)+log_{10}(25)=2 is x=2,x=-2
Solve for x: log_{10}(x^2)+log_{10}(25)=2
The solution is x=2,x=-2