What is the answer to log_{2}(X+2)+log_{2}(X-1)=2 ?

The answer to log_{2}(X+2)+log_{2}(X-1)=2 is X=2

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log_{2}(X+2)+log_{2}(X-1)=2

lo g_{2} (X + 2) + lo g_{2} (X - 1) = 2

X = 2

Solution steps

lo g_{2} (X + 2) + lo g_{2} (X - 1) = 2

Apply log rules

(X + 2) (X - 1) = 4

Solve

(X + 2) (X - 1) = 4 : X = 2, X = - 3

X = 2, X = - 3

Verify Solutions:

X = 2

True

, X = - 3

False

The solution is

X = 2

lo g_{x} (\frac{1}{16}) = - 2

\frac{1 - ln ( x )}{x ^{2}} = 0

lo g_{10} (16 x) - lo g_{10} (4) = 2

lo g_{3} (x^{2} - 5 x + 3) = 2

ln (x) = - \frac{1}{2}

What is the answer to log_{2}(X+2)+log_{2}(X-1)=2 ?
The answer to log_{2}(X+2)+log_{2}(X-1)=2 is X=2
Solve for X: log_{2}(X+2)+log_{2}(X-1)=2
The solution is X=2