What is the answer to log_{10}(4)+log_{10}(2x)=log_{10}(24) ?

The answer to log_{10}(4)+log_{10}(2x)=log_{10}(24) is x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(4)+log_{10}(2x)=log_{10}(24)

lo g_{10} (4) + lo g_{10} (2 x) = lo g_{10} (24)

x = 3

Solution steps

lo g_{10} (4) + lo g_{10} (2 x) = lo g_{10} (24)

Move

lo g_{10} (4)

to the right side

lo g_{10} (2 x) = lo g_{10} (24) - lo g_{10} (4)

Apply log rules

2 x = 6

Solve

2 x = 6 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{2} (x - 4) = 5

e^{x l n (x)} = x^{2}

lo g_{4 - x} (4) = 2

lo g_{3} (7 - 2 x) = 2

0 = ln (x)

What is the answer to log_{10}(4)+log_{10}(2x)=log_{10}(24) ?
The answer to log_{10}(4)+log_{10}(2x)=log_{10}(24) is x=3
Solve for x: log_{10}(4)+log_{10}(2x)=log_{10}(24)
The solution is x=3