What is the answer to 2log_{7}(-2x)=0 ?

The answer to 2log_{7}(-2x)=0 is x=-1/2

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2log_{7}(-2x)=0

2 lo g_{7} (- 2 x) = 0

x = - \frac{1}{2}

Decimal

x = - 0.5

Solution steps

2 lo g_{7} (- 2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

lo g_{7} (- 2 x) = 0

Solve

lo g_{7} (- 2 x) = 0 : x = - \frac{1}{2}

Verify Solutions:

x = - \frac{1}{2}

True

The solution is

x = - \frac{1}{2}

lo g_{10} (x - 15) - 2 = - lo g_{10} (x)

lo g_{10} (x) + lo g_{10} (x + 3) = 1

lo g_{0.25} (x) = \frac{5}{2}

lo g_{2} (x - 3) = 4

lo g_{2} (a) = - 1