What is the answer to log_{10}(-x)+log_{10}(1-2x)=1 ?

The answer to log_{10}(-x)+log_{10}(1-2x)=1 is x=-2

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log_{10}(-x)+log_{10}(1-2x)=1

lo g_{10} (- x) + lo g_{10} (1 - 2 x) = 1

x = - 2

Solution steps

lo g_{10} (- x) + lo g_{10} (1 - 2 x) = 1

Apply log rules

- x (1 - 2 x) = 10

Solve

- x (1 - 2 x) = 10 : x = \frac{5}{2}, x = - 2

x = \frac{5}{2}, x = - 2

Verify Solutions:

x = \frac{5}{2}

False

, x = - 2

True

The solution is

x = - 2

lo g_{7} (2 x + 1) = 2

lo g_{a} (216) = 3

lo g_{3} (11 - 4 x) = 3

lo g_{10} (3 x - 2) = 2

lo g_{2} (b) = - 5

What is the answer to log_{10}(-x)+log_{10}(1-2x)=1 ?
The answer to log_{10}(-x)+log_{10}(1-2x)=1 is x=-2
Solve for x: log_{10}(-x)+log_{10}(1-2x)=1
The solution is x=-2