What is the answer to log_{10}(x)+log_{10}(x+21)=2 ?

The answer to log_{10}(x)+log_{10}(x+21)=2 is x=4

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log_{10}(x)+log_{10}(x+21)=2

lo g_{10} (x) + lo g_{10} (x + 21) = 2

x = 4

Solution steps

lo g_{10} (x) + lo g_{10} (x + 21) = 2

Apply log rules

x (x + 21) = 100

Solve

x (x + 21) = 100 : x = 4, x = - 25

x = 4, x = - 25

Verify Solutions:

x = 4

True

, x = - 25

False

The solution is

x = 4

lo g_{3} ((x^{2} + 2)^{2}) = 6

6 lo g_{3} (0.5 x) = 11

3 ln (x) + 5 ln (3) = ln (\frac{3}{x})

lo g_{x} (3) = 1

lo g_{x} (0.04) = - 2

What is the answer to log_{10}(x)+log_{10}(x+21)=2 ?
The answer to log_{10}(x)+log_{10}(x+21)=2 is x=4
Solve for x: log_{10}(x)+log_{10}(x+21)=2
The solution is x=4