What is the answer to 2log_{10}(x)=log_{10}(2)+log_{10}(3x-4) ?

The answer to 2log_{10}(x)=log_{10}(2)+log_{10}(3x-4) is x=4,x=2

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2log_{10}(x)=log_{10}(2)+log_{10}(3x-4)

2 lo g_{10} (x) = lo g_{10} (2) + lo g_{10} (3 x - 4)

x = 4, x = 2

Solution steps

2 lo g_{10} (x) = lo g_{10} (2) + lo g_{10} (3 x - 4)

Apply log rules

x^{2} = 2 (3 x - 4)

Solve

x^{2} = 2 (3 x - 4) : x = 4, x = 2

x = 4, x = 2

Verify Solutions:

x = 4

True

, x = 2

True

The solutions are

x = 4, x = 2

a, lo g_{a} (b) = c

lo g_{2} (x - 4) = 6

0.34 = lo g_{10} (x)

20 x^{3} ln (x) + 9 x^{3} = 0

lo g_{10} (x + 3) + lo g_{10} (x) = 1

What is the answer to 2log_{10}(x)=log_{10}(2)+log_{10}(3x-4) ?
The answer to 2log_{10}(x)=log_{10}(2)+log_{10}(3x-4) is x=4,x=2
Solve for x: 2log_{10}(x)=log_{10}(2)+log_{10}(3x-4)
The solution is x=4,x=2