What is the answer to 5x^4ln(x)+x^4=0 ?

The answer to 5x^4ln(x)+x^4=0 is x= 1/(\sqrt[5]{e)}

Solve for x: 5x^4ln(x)+x^4=0

The solution is x= 1/(\sqrt[5]{e)}

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5 x^{4} ln (x) + x^{4} = 0

x = \frac{1}{5 e}

Decimal

x = 0.81873 \dots

Solution steps

5 x^{4} ln (x) + x^{4} = 0

Move

x^{4}

to the right side

5 x^{4} ln (x) = - x^{4}

Move

x^{4}

to the left side

5 x^{4} ln (x) + x^{4} = 0

Factor

5 x^{4} ln (x) + x^{4} : x^{4} (5 ln (x) + 1)

x^{4} (5 ln (x) + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 ln (x) + 1 = 0

Solve

5 ln (x) + 1 = 0 : x = \frac{1}{5 e}

Verify Solutions:

x = 0

False

, x = \frac{1}{5 e}

True

The solution is

x = \frac{1}{5 e}

4 = lo g_{10} (\frac{250}{x})

lo g_{2} (5 - x) = 3

ln (x) = 4

ln (x) = 8

3 lo g_{4} (x - 2) = 5

What is the answer to 5x^4ln(x)+x^4=0 ?
The answer to 5x^4ln(x)+x^4=0 is x= 1/(\sqrt[5]{e)}
Solve for x: 5x^4ln(x)+x^4=0
The solution is x= 1/(\sqrt[5]{e)}