What is the answer to log_{2}((x+4)^2)=4 ?

The answer to log_{2}((x+4)^2)=4 is x=0,x=-8

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log_{2}((x+4)^2)=4

lo g_{2} ((x + 4)^{2}) = 4

x = 0, x = - 8

Solution steps

lo g_{2} ((x + 4)^{2}) = 4

Apply log rules

(x + 4)^{2} = 16

Solve

(x + 4)^{2} = 16 : x = 0, x = - 8

x = 0, x = - 8

- 2 lo g_{4} (3 x) + 2 = - 6

lo g_{\frac{1}{2}} (2 x - 4) = - 2

lo g_{8} (x) = \frac{4}{3}

ln (x) + ln (x + 1) = 1

lo g_{x} (5) = - \frac{1}{2}

What is the answer to log_{2}((x+4)^2)=4 ?
The answer to log_{2}((x+4)^2)=4 is x=0,x=-8
Solve for x: log_{2}((x+4)^2)=4
The solution is x=0,x=-8