What is the answer to 2log_{10}(x)-log_{10}(6)=log_{10}(486) ?

The answer to 2log_{10}(x)-log_{10}(6)=log_{10}(486) is x=54

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2log_{10}(x)-log_{10}(6)=log_{10}(486)

2 lo g_{10} (x) - lo g_{10} (6) = lo g_{10} (486)

x = 54

Solution steps

2 lo g_{10} (x) - lo g_{10} (6) = lo g_{10} (486)

Move

lo g_{10} (6)

to the right side

2 lo g_{10} (x) = lo g_{10} (486) + lo g_{10} (6)

Divide both sides by

2

lo g_{10} (x) = \frac{lo g _{10} ( 486 ) + lo g _{10} ( 6 )}{2}

Apply log rules

x = 54

Verify Solutions:

x = 54

True

The solution is

x = 54

y, x = lo g_{10} (y)

4 ln (x^{2}) - 7 ln (x) + ln (x + 3) = 0

6 ln (x) - 3 = 2 - ln (x)

lo g_{8} (28 k - 20) + 15 = 18

2 ln (x) = ln (2) + ln (x + 4)

What is the answer to 2log_{10}(x)-log_{10}(6)=log_{10}(486) ?
The answer to 2log_{10}(x)-log_{10}(6)=log_{10}(486) is x=54
Solve for x: 2log_{10}(x)-log_{10}(6)=log_{10}(486)
The solution is x=54