What is the answer to log_{10}(2x+3)=log_{10}(45)-log_{10}(3) ?

The answer to log_{10}(2x+3)=log_{10}(45)-log_{10}(3) is x=6

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log_{10}(2x+3)=log_{10}(45)-log_{10}(3)

lo g_{10} (2 x + 3) = lo g_{10} (45) - lo g_{10} (3)

x = 6

Solution steps

lo g_{10} (2 x + 3) = lo g_{10} (45) - lo g_{10} (3)

Apply log rules

2 x + 3 = 15

Solve

2 x + 3 = 15 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

lo g_{2} (3 x^{2} - 4 x) = 5

lo g_{2} (4 x + 5) = 4

lo g_{\frac{1}{2}} (3 - x) = - 3

lo g_{3} (x^{2} + 1) = 2

lo g_{7} (x) = - 1

What is the answer to log_{10}(2x+3)=log_{10}(45)-log_{10}(3) ?
The answer to log_{10}(2x+3)=log_{10}(45)-log_{10}(3) is x=6
Solve for x: log_{10}(2x+3)=log_{10}(45)-log_{10}(3)
The solution is x=6