What is the answer to log_{10}(4x)+log_{10}(3)=log_{10}(84) ?

The answer to log_{10}(4x)+log_{10}(3)=log_{10}(84) is x=7

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log_{10}(4x)+log_{10}(3)=log_{10}(84)

lo g_{10} (4 x) + lo g_{10} (3) = lo g_{10} (84)

x = 7

Solution steps

lo g_{10} (4 x) + lo g_{10} (3) = lo g_{10} (84)

Move

lo g_{10} (3)

to the right side

lo g_{10} (4 x) = lo g_{10} (84) - lo g_{10} (3)

Apply log rules

4 x = 28

Solve

4 x = 28 : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

lo g_{7} (- 5 - x) = 3

ln (x + 1) = 2 - 2 x

lo g_{16} (3 x + 1) = 2

ln^{2} (x) - ln (x) - 2 = 0

20 lo g_{10} (x) = 60

What is the answer to log_{10}(4x)+log_{10}(3)=log_{10}(84) ?
The answer to log_{10}(4x)+log_{10}(3)=log_{10}(84) is x=7
Solve for x: log_{10}(4x)+log_{10}(3)=log_{10}(84)
The solution is x=7