What is the answer to log_{2}(x^2-3x+10)=3 ?

The answer to log_{2}(x^2-3x+10)=3 is x=2,x=1

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log_{2}(x^2-3x+10)=3

lo g_{2} (x^{2} - 3 x + 10) = 3

x = 2, x = 1

Solution steps

lo g_{2} (x^{2} - 3 x + 10) = 3

Apply log rules

x^{2} - 3 x + 10 = 8

Solve

x^{2} - 3 x + 10 = 8 : x = 2, x = 1

x = 2, x = 1

lo g_{3} (x + 3) = 2

lo g_{5} (3 x + 5) = 3

ln (x) = 9

15 lo g_{10} (6 x) = - 15

3 lo g_{3} (n + 2) = 2 n - 3

What is the answer to log_{2}(x^2-3x+10)=3 ?
The answer to log_{2}(x^2-3x+10)=3 is x=2,x=1
Solve for x: log_{2}(x^2-3x+10)=3
The solution is x=2,x=1