What is the answer to log_{2}(1-3x)=3 ?

The answer to log_{2}(1-3x)=3 is x=-7/3

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log_{2}(1-3x)=3

lo g_{2} (1 - 3 x) = 3

x = - \frac{7}{3}

Decimal

x = - 2.33333 \dots

Solution steps

lo g_{2} (1 - 3 x) = 3

Apply log rules

1 - 3 x = 8

Solve

1 - 3 x = 8 : x = - \frac{7}{3}

x = - \frac{7}{3}

lo g_{10} (x^{3}) = lo g_{10} (6) + 2 lo g_{10} (x)

ln (\frac{x + 1 + e ^{2}}{x + 1}) = 2

lo g_{10} (x) = 0.001

x, ln (x) = t

y, x = 20 lo g_{10} (y)