What is the answer to log_{2}(x^2-5x-4)=1 ?

The answer to log_{2}(x^2-5x-4)=1 is x=6,x=-1

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log_{2}(x^2-5x-4)=1

lo g_{2} (x^{2} - 5 x - 4) = 1

x = 6, x = - 1

Solution steps

lo g_{2} (x^{2} - 5 x - 4) = 1

Apply log rules

x^{2} - 5 x - 4 = 2

Solve

x^{2} - 5 x - 4 = 2 : x = 6, x = - 1

x = 6, x = - 1

lo g_{x} (e) = - 3

lo g_{x} (256) = - 8

lo g_{10} (x) - lo g_{10} (8) = 3

lo g_{10} (x + 12) = lo g_{10} (x) + lo g_{10} (12)

lo g_{3} (x) = - 5

What is the answer to log_{2}(x^2-5x-4)=1 ?
The answer to log_{2}(x^2-5x-4)=1 is x=6,x=-1
Solve for x: log_{2}(x^2-5x-4)=1
The solution is x=6,x=-1