What is the answer to 3-log_{10}(x+2)=5 ?

The answer to 3-log_{10}(x+2)=5 is x=-199/100

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3-log_{10}(x+2)=5

3 - lo g_{10} (x + 2) = 5

x = - \frac{199}{100}

Decimal

x = - 1.99

Solution steps

3 - lo g_{10} (x + 2) = 5

Move

3

to the right side

- lo g_{10} (x + 2) = 2

Divide both sides by

- 1

lo g_{10} (x + 2) = - 2

Apply log rules

x + 2 = \frac{1}{100}

Solve

x + 2 = \frac{1}{100} : x = - \frac{199}{100}

x = - \frac{199}{100}

Verify Solutions:

x = - \frac{199}{100}

True

The solution is

x = - \frac{199}{100}

(ln (x))^{2} = ln (x)

lo g_{x} (381) = - 2

(ln (x))^{2} - ln (x^{2}) + 1 = 0

lo g_{2} (3 - x) = 0

ln (4 x e^{x - 1}) = x

What is the answer to 3-log_{10}(x+2)=5 ?
The answer to 3-log_{10}(x+2)=5 is x=-199/100
Solve for x: 3-log_{10}(x+2)=5
The solution is x=-199/100