What is the answer to ln(x^2)=-1 ?

The answer to ln(x^2)=-1 is x=sqrt(1/e),x=-sqrt(1/e)

Solve for x: ln(x^2)=-1

The solution is x=sqrt(1/e),x=-sqrt(1/e)

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ln (x^{2}) = - 1

x = \frac{1}{e}, x = - \frac{1}{e}

Decimal

x = 0.60653 \dots, x = - 0.60653 \dots

Solution steps

ln (x^{2}) = - 1

Apply log rules

x^{2} = \frac{1}{e}

Solve

x^{2} = \frac{1}{e} : x = \frac{1}{e}, x = - \frac{1}{e}

x = \frac{1}{e}, x = - \frac{1}{e}

x, 2 x ln (x) + x = 0

lo g_{216} (x) = - \frac{1}{3}

lo g_{10} (3 x + 7) = 2

0 = x ln (3 x - 5)

ln (3 x - 5) = 6

What is the answer to ln(x^2)=-1 ?
The answer to ln(x^2)=-1 is x=sqrt(1/e),x=-sqrt(1/e)
Solve for x: ln(x^2)=-1
The solution is x=sqrt(1/e),x=-sqrt(1/e)