What are the solutions to the equation x^2-7(x+6)=x+59 ?

The solutions to the equation x^2-7(x+6)=x+59 are x=4+3sqrt(13),x=4-3sqrt(13)

Find the zeros of x^2-7(x+6)=x+59

The zeros of x^2-7(x+6)=x+59 are x=4+3sqrt(13),x=4-3sqrt(13)

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x^{2} - 7 (x + 6) = x + 59

x = 4 + 313, x = 4 - 313

Decimal Notation

x = 14.81665 \dots, x = - 6.81665 \dots

Solution steps

x^{2} - 7 (x + 6) = x + 59

Expand

x^{2} - 7 (x + 6) : x^{2} - 7 x - 42

x^{2} - 7 x - 42 = x + 59

Move

59

to the left side

x^{2} - 7 x - 101 = x

Move

x

to the left side

x^{2} - 8 x - 101 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 101 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 101) = 613

x_{1, 2} = \frac{- ( - 8 ) \pm 6 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 6 13}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 6 13}{2 \cdot 1}

x = \frac{- ( - 8 ) + 6 13}{2 \cdot 1} : 4 + 313

x = \frac{- ( - 8 ) - 6 13}{2 \cdot 1} : 4 - 313

The solutions to the quadratic equation are:

x = 4 + 313, x = 4 - 313

x - 4 x < - 15

∣ 2 x + 3 ∣ > 7

2 x + 9 < 3

3 x + 1 > 3 (x + 2)

332

What are the solutions to the equation x^2-7(x+6)=x+59 ?
The solutions to the equation x^2-7(x+6)=x+59 are x=4+3sqrt(13),x=4-3sqrt(13)
Find the zeros of x^2-7(x+6)=x+59
The zeros of x^2-7(x+6)=x+59 are x=4+3sqrt(13),x=4-3sqrt(13)