What is the answer to log_{2}(3x+1)=3 ?

The answer to log_{2}(3x+1)=3 is x= 7/3

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log_{2}(3x+1)=3

lo g_{2} (3 x + 1) = 3

x = \frac{7}{3}

Decimal

x = 2.33333 \dots

Solution steps

lo g_{2} (3 x + 1) = 3

Apply log rules

3 x + 1 = 8

Solve

3 x + 1 = 8 : x = \frac{7}{3}

x = \frac{7}{3}

lo g_{5} (x - 5) = 3

y, ln (x) = - ln (y)

4.2 = 4.75 + lo g_{10} (x)

lo g_{4} (k^{2} - 2 k + 1) = - 1

lo g_{x} (5) = - 1