What is the answer to log_{10}(x^2+9x)=1 ?

The answer to log_{10}(x^2+9x)=1 is x=1,x=-10

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log_{10}(x^2+9x)=1

lo g_{10} (x^{2} + 9 x) = 1

x = 1, x = - 10

Solution steps

lo g_{10} (x^{2} + 9 x) = 1

Apply log rules

x^{2} + 9 x = 10

Solve

x^{2} + 9 x = 10 : x = 1, x = - 10

x = 1, x = - 10

\frac{ln ( x )}{ln ( x )} = 3

lo g_{3} (6 x - 2) = 2

3 ln (5 x) = 10

lo g_{10} (3 x) = 2

lo g_{10} (x) + lo g_{10} (x - 99) = 2

What is the answer to log_{10}(x^2+9x)=1 ?
The answer to log_{10}(x^2+9x)=1 is x=1,x=-10
Solve for x: log_{10}(x^2+9x)=1
The solution is x=1,x=-10