What is the answer to 12x^2ln(x)+7x^2=0 ?

The answer to 12x^2ln(x)+7x^2=0 is x= 1/(e^{7/12)}

Solve for x: 12x^2ln(x)+7x^2=0

The solution is x= 1/(e^{7/12)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} ln (x) + 7 x^{2} = 0

x = \frac{1}{e ^{\frac{7}{12}}}

Decimal

x = 0.55803 \dots

Solution steps

12 x^{2} ln (x) + 7 x^{2} = 0

Move

7 x^{2}

to the right side

12 x^{2} ln (x) = - 7 x^{2}

Move

7 x^{2}

to the left side

12 x^{2} ln (x) + 7 x^{2} = 0

Factor

12 x^{2} ln (x) + 7 x^{2} : x^{2} (12 ln (x) + 7)

x^{2} (12 ln (x) + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 12 ln (x) + 7 = 0

Solve

12 ln (x) + 7 = 0 : x = \frac{1}{e ^{\frac{7}{12}}}

Verify Solutions:

x = 0

False

, x = \frac{1}{e ^{\frac{7}{12}}}

True

The solution is

x = \frac{1}{e ^{\frac{7}{12}}}

lo g_{10} (3 x + 1) = 2

lo g_{10} (x) 5 = lo g_{10} (5 x)

2 lo g_{5} (6 x + 5) = 6

5 + 2 ln (x) = 8

lo g_{b} (15) = 1

What is the answer to 12x^2ln(x)+7x^2=0 ?
The answer to 12x^2ln(x)+7x^2=0 is x= 1/(e^{7/12)}
Solve for x: 12x^2ln(x)+7x^2=0
The solution is x= 1/(e^{7/12)}