What is the answer to solvefor y,x=2y+ln(y) ?

The answer to solvefor y,x=2y+ln(y) is y=(\W(2e^x))/2

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solvefor y,x=2y+ln(y)

solve for

y, x = 2 y + ln (y)

y = \frac{W ( 2 e ^{x} )}{2}

Solution steps

x = 2 y + ln (y)

Switch sides

2 y + ln (y) = x

Move

2 y

to the right side

ln (y) = x - 2 y

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (y)} = e^{x - 2 y}

Simplify

e^{l n (y)} : y

y = e^{x - 2 y}

Solve

y = e^{x - 2 y} : y = \frac{W ( 2 e ^{x} )}{2}

y = \frac{W ( 2 e ^{x} )}{2}

Verify Solutions:

y = \frac{W ( 2 e ^{x} )}{2}

True

The solution is

y = \frac{W ( 2 e ^{x} )}{2}

lo g_{7} (x + 2) = - 2

lo g_{\frac{1}{2}} (3 x - 1) = - 3

lo g_{3} (x - 2) = 4

lo g_{9} (x) = 0.5

3 lo g_{10} (x) - lo g_{10} (32) = lo g_{10} (\frac{x}{2})

What is the answer to solvefor y,x=2y+ln(y) ?
The answer to solvefor y,x=2y+ln(y) is y=(\W(2e^x))/2