What is the answer to log_{2}(x)+log_{2}(4)=log_{2}(16) ?

The answer to log_{2}(x)+log_{2}(4)=log_{2}(16) is x=4

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log_{2}(x)+log_{2}(4)=log_{2}(16)

lo g_{2} (x) + lo g_{2} (4) = lo g_{2} (16)

x = 4

Solution steps

lo g_{2} (x) + lo g_{2} (4) = lo g_{2} (16)

Move

lo g_{2} (4)

to the right side

lo g_{2} (x) = lo g_{2} (16) - lo g_{2} (4)

Apply log rules

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

5 - lo g_{3} (x - 1) = 0

lo g_{x} (\frac{1}{1000}) = - 3

lo g_{10} (x + 9) = 1 - lo g_{10} (x)

20 = 20 lo g_{10} (x)

6 = lo g_{2} (x)

What is the answer to log_{2}(x)+log_{2}(4)=log_{2}(16) ?
The answer to log_{2}(x)+log_{2}(4)=log_{2}(16) is x=4
Solve for x: log_{2}(x)+log_{2}(4)=log_{2}(16)
The solution is x=4