What is the answer to log_{2}(x^2+4x+3)=3 ?

The answer to log_{2}(x^2+4x+3)=3 is x=1,x=-5

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log_{2}(x^2+4x+3)=3

lo g_{2} (x^{2} + 4 x + 3) = 3

x = 1, x = - 5

Solution steps

lo g_{2} (x^{2} + 4 x + 3) = 3

Apply log rules

x^{2} + 4 x + 3 = 8

Solve

x^{2} + 4 x + 3 = 8 : x = 1, x = - 5

x = 1, x = - 5

lo g_{2 x} (3 x^{2} + 9 x - 14) = 2

2 + 3 ln (x) = 7

2 lo g_{10} (x) = lo g_{10} (x) + 3

lo g_{x} (2) = - \frac{1}{2}

lo g_{x - 3} (81) = 4

What is the answer to log_{2}(x^2+4x+3)=3 ?
The answer to log_{2}(x^2+4x+3)=3 is x=1,x=-5
Solve for x: log_{2}(x^2+4x+3)=3
The solution is x=1,x=-5